#!/usr/bin/env python # -*- coding: utf-8 -*- # Copyright 1999-2020 Alibaba Group Holding Ltd. # # Licensed under the Apache License, Version 2.0 (the "License"); # you may not use this file except in compliance with the License. # You may obtain a copy of the License at # # http://www.apache.org/licenses/LICENSE-2.0 # # Unless required by applicable law or agreed to in writing, software # distributed under the License is distributed on an "AS IS" BASIS, # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. # See the License for the specific language governing permissions and # limitations under the License. import numpy as np from ... import opcodes as OperandDef from ..utils import infer_dtype from .core import TensorUnaryOp from .utils import arithmetic_operand @arithmetic_operand(sparse_mode='unary') class TensorCosh(TensorUnaryOp): _op_type_ = OperandDef.COSH _func_name = 'cosh' [docs]@infer_dtype(np.cosh) def cosh(x, out=None, where=None, **kwargs): """ Hyperbolic cosine, element-wise. Equivalent to ``1/2 * (mt.exp(x) + mt.exp(-x))`` and ``mt.cos(1j*x)``. Parameters ---------- x : array_like Input tensor. out : Tensor, None, or tuple of Tensor and None, optional A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or `None`, a freshly-allocated tensor is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs. where : array_like, optional Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone. **kwargs Returns ------- out : Tensor Output array of same shape as `x`. Examples -------- >>> import mars.tensor as mt >>> mt.cosh(0).execute() 1.0 The hyperbolic cosine describes the shape of a hanging cable: >>> import matplotlib.pyplot as plt >>> x = mt.linspace(-4, 4, 1000) >>> plt.plot(x.execute(), mt.cosh(x).execute()) >>> plt.show() """ op = TensorCosh(**kwargs) return op(x, out=out, where=where)